Math, asked by hasanansari220904, 4 days ago

Construct ∆ABC with AB = 5.5 cm, AC = 7 cm and m∠C = 45°. 3 OR Construct the right angled ∆PQR, where m∠Q = 90°, QR = 5 cm and PR = 6 cm.​

Answers

Answered by ParikshitPulliwar
0

Answer: To construct: A right angled  △PQR where m∠Q=90  

o

, QR=8cm and PR=10cm.

Steps of construction:

(a) Draw a line segment QR=8cm

(b) At point Q, draw QX⊥QR

(c) Taking R as centre, draw an arc of radius 10cm

(d) This arc cuts QX at point P

(e) Join PQ

It is the required right angled triangle PQR

Answered by 101Jaatni
1

Answer:

Step 1- DRAW A LINE SEGMENT QR=5CM

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