Construct ΔABC with AB= 5cm Angle A=600 and BC+AC =12 cm
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Step-by-step explanation:
It is a Four-Step Construction
Step-by-step explanation:
The Steps of Construction are -
1.) Draw AB = 5 cm as a line segment and make an angle A = 45°, Let it be ∠XAB.
2.) With A as the center, draw an arc of 2.5 cm (AC - BC) length, in order to cut AX at point D.
3.) After joining BD, draw a perpendicular bisector PQ of BD, intersecting AX at C.
4.) Join BC.
ΔABC is the required triangle.
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using SSS criterion
Step-by-step explanation:
answer in attachement...hope it helps
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