Question

Construct ABCD in which AB=6cm BC=5cm angleA=55° angleB=110° angleD=90°

Answer 1

Step-by-step explanation:

⇒ Draw a line segment AB = 6cm.

⇒ Construct an angle of 60

∘

at point B.

⇒ Cut off BC = 4cm.

⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120

∘

at point A and C which meet at point D.

⇒ Thus, ABCD is a required parallelogram.

⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )

⇒ Perimeter of parallelogram ABCD=2(a+b)

⇒ 2(6+4) [From( 1 )]

∴ Perimeter of parallelogram ABCD=20cm.