Construct ADEF such that DE= 5cm, DF=3cm and LEDF=90°
Please give the answer in step by step
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Step-by-step explanation:
First we draw a rough sketch
To construct it, we follow these steps
1. Draw a line segment DF of length 3cm
2. Now, make 90° angle from point D
3. Taking D as center,
5cm as radius, we draw an arc
let the point where arc intersects
the ray be point E
4. Join EF
and label the sides
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