Question

Construct ALMN, right-angled at M, given that LN = 5 cm and MN = 3 cm.​

Answer 1

Step-by-step explanation:

Here are steps of construction:

First of all draw a line segment MN=3cm

Using a compass draw an angle of 90° at M i.e.<NMQ= 90°

(Using Pythogoras theorem we get LM= 4cm)

Mark an arc on ray MQ taking the radius of compass= 4cm, name the point of intersection

as L

Join L to N

∆LMN is the required triangle

Please please please mark me brainliest