construct an ΔABC in which bc=3.6cm, ab= 5cm, AC= 5.4cm. Draw a perpendicular bisector of the side BC
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Answer:
first make a line of 3.6 cm
than take divider
naap lo usme 5 cm fir line
ke ek side end par rakh kar draw kro circle
fir naap lo 5.4 fir ek end pe circle draw kro
or fir jaha circle meet ho wahi se line ko draw kro
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