Question

construct an angle ABC = 90 degree locate a point P which is 2.5 cm from AB and 3.2 cm from BC.

Answer 1

I don't know this is right or wrong. This question is new for me.

Hope it will right figure

Answer 2

angle ABC = 90 degree

Step-by-step explanation:

given  data

angle ABC = 90 degree

P from AB =  2.5 cm

P from BC =  3.2 cm

solution

step (1) first we draw  angle ABC = 90°

step (2) now from point B , cut a arc 3.2 cm

step (3) after that by C we draw a perpendicular  CH ⊥ BC and cut at CE at 3.2 cm and join DE

step (4) now we get DE parallel BC  at distance 3.2 from BC

step (5) now at BC that cut BM at distance 2.5 cm

step (6) at point A we draw a perpendicular  AK ⊥ AB and AK cut  here AN is 2.5 cm

step (7) now join NM and it is parallel to AB at distance 2.5 cm from AB

step (8) now DE and MN both intersect each other at point  P which is 3.2 cm from BC and 2.5 cm from AB  

Learn more :

construct an angle ABC

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