Question

Construct an angle abc = 90 degree. Locate a point p which is 2.5 from ab and 3.2 from bc

Answer 1

Answer:

Step-by-step explanation:

 

1. Draw ∠ABC = 90° 2. From AB, cut BD = 3.2 cm.  

3. Through point C, draw CH⊥BC. From CH, cut CE = 3.2. Join DE. Now DE is a line parallel to BC and at a distance of 3.2 cm from BC.  

4. From BC cut BM = 2.5 cm.

5. Through point A, draw AK ⊥ AB. From AK cut AN = 2.5 cm. Join NM. Therefore NM is parallel to AB and at a distance of 2.5 cm from AB.

6. DE and MN intersect each other at P. Thus P is the required point which is 2.5 cm from AB and 3.2 cm from BC