Question

Construct an angle abc =90degree .Locate a point p which is 2.5cm from ab and 3.2cm from bc

Answer 1

Answer:

1. Draw ∠ABC = 90° 2. From AB, cut BD = 3.2 cm.  3. Through point C, draw CH⊥BC. From CH, cut CE = 3.2. Join DE. Now DE is a line parallel to BC and at a distance of 3.2 cm from BC.  4. From BC cut BM = 2.5 cm. 5. Through point A, draw AK ⊥ AB. From AK cut AN = 2.5 cm. Join NM. Therefore NM is parallel to AB and at a distance of 2.5 cm from AB. 6. DE and MN intersect each other at P. Thus P is the required point which is 2.5 cm from AB and 3.2 cm from BCRead more on Sarthaks.com - https://www.sarthaks.com/170879/construct-an-angle-abc-90-locate-a-point-p-which-is-2-5-cm-from-ab-and-3-2-cm-from-bc