Construct an angle of 45° at the initial point of a given ray and justify the construction.
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Answer:
draw a 90° and bisect it
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Hey mate! Here is your answer:
STEPS OF CONSTRUCTION:-
1)Draw a ray OA .
2)With O as centre and any suitable radius draw an arc cutting OA at B .
3)With B as centre and same radius cut the previous drawn. arc at C and then with C as centre and radius cut the arc at D.
4(With C as centre and radius more than half Cd draw an arc .
5)With D as centre and same radius draw another arc to cut the previous arc at E.
6)Join OE ,then angle AOE ==90°.
7)Draw the bisector OF of Angle AOE ,then Angle AOF =45°.
Justify......
By construction.
Angle AOE ==90° and OF is the bisector of Angle AoE
So, Angle =1/2/_AOE =1/2×90°==45°
Hope it helps you ✌
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