Construct an equilateral trangle given its side 5cm
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Let Δ ABC is a Equilateral triangle
(1) Draw AB as base = 5 cm
(2) Draw perpendicular bisector of AB
(3) Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector
(4) Do the same with point B and wherever those arcs meet name that point C
(5) Thus ABC is the required ∆.
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