Question

construct an equilateral triangle ABC in which BC = 6 CM

Answer 1

Step-by-step explanation:

Steps of Construction :

(i) Draw a line segment BC = 6 cm

(ii) With centres B and C and radius 6 cm, draw two arcs intersecting each other at A.

(iii) Join AB and AC

∆ ABC is the required equilateral triangle,

(iv) Draw the angle bisectors of ∠A, ∠B and ∠C.

These are the lines of symmetry which are three in numbers as the triangle is equilateral.