Construct an equilateral triangle ABC with side 5cm.
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(1)Draw AB as base = 5 cm. (2) Draw perpendicular bisector of AB. (3) Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector.(4) Do the same with point B and wherever those arcs meet name that point C.
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Step-by-step explanation:
We know that,
Equilateral triangle means all the sides of a triangle are equal.
ΔABC has to be constructed with AB=BC=CA=5cm.
Then,
Draw a line segment BC of 5cm.
Taking point B as center, draw an arc of 5cm as radius.
Both arc will intersect at point A.
Join A and B; A and C.
ABC is the required equilateral triangle.
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