Question

construct an equilateral triangle angle LMN and one of whose side is 5 cm. Bisector angle M of the triangle

Answer 1

Answer:

Step-by-step explanation:

Steps of construction:

1.Draw a line segment LM = 5 cm.

2.Taking L as centre and radius 5 cm draw an arc.

3.Taking M as centre and radius draw an other arc intersecting previous arc at N.

4.Join LN and MN. Thus, ΔLMN is the required equilateral triangle.

5.Taking M as centre and any suitable radius, draw an arc intersecting LM at P and MN at Q.

6.Taking P and Q as centres and same radii, draw arcs intersecting at S.

7.Join MS and produce it meet LN at R. Thus, MSR is the required bisector of ∠M.

Answer 2

Step-by-step explanation:

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