Construct an equilateral triangle each of whose altitudes measures 5.4 cm
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Answered by
11
Answer:
Step-by-step explanation
Draw a base of5.8cm using a ruler now open compass and draw 2 seva from each end and join both the ends
From the point where both arcs meet
And we get a equilateral triangle
Answered by
45
steps:
1) draw a line XY.
2) Mark any point P on it.
3) From P, construct PQ perpendicular to XY.
4) Using a compass, take P as centre and 5.4 cm as the radius and cutting PQ at A.
5) Construct angle-PAB=30° and
angle-PAC=30°, meeting XY at B and C respectively.
1) draw a line XY.
2) Mark any point P on it.
3) From P, construct PQ perpendicular to XY.
4) Using a compass, take P as centre and 5.4 cm as the radius and cutting PQ at A.
5) Construct angle-PAB=30° and
angle-PAC=30°, meeting XY at B and C respectively.
Attachments:
titanium001:
I don't know the exact measurement of XY but you can see the image for understanding
Please mark my answer as Brainliest.
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