Construct an equilateral triangle if its altitude is 6 cm.
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- Draw any line l.
- Take any point M on it and draw a line p perpendicular to l.
- With M as centre, cut off MC = 6 cm.
- 4.At C, with initial line CM construct angles of measures 30° on both sides and let these lines intersect line l in A and B. Thus, ΔABC is the required triangle.
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Draw any line l.
Take any point M on it and draw a line p perpendicular to l.
With M as centre, cut off MC = 6 cm.
4.At C, with initial line CM construct angles of measures 30° on both sides and let these lines intersect line l in A and B. Thus, ΔABC is the required triangle.
Attachments:
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