Question

construct an equilateral triangle of 4.5 cm .​

Answer 1

Construction :  

Step 1: Draw a line segment AB of length 4.5 cms.  

Step 2: Take 4.5 cms as radius and A as center, draw an arc.

Step 3: Take 4.5 cms as radius and B as center, draw and arc.  

Step 4: Let C be the point where the two arcs intersect, join AC and BC and label the sides.  

Thus, triangle ABC is the required equilateral triangle.  

Justification :  

By construction, AB=BC=CA ( Radius of equal arcs)

Since all sides are equal.  Therefore, triangle ABC is an equilateral triangle.  

Thus, the construction is justified.

Answer 2

Step-by-step explanation:

• ☞Draw a line segment AB of length 4.5 cm
• ☞Take 4.5 cms as radius and A as center, draw an arc.
• ☞ Take 4.5 cms as radius and B as center, draw and arc.
• ☞Let C be the point where the two arcs intersect, join AC and BC and label the sides.

Thus, triangle ABC is the required equilateral triangle.

Justification :

By construction, AB=BC=CA ( Radius of equal arcs)

Since all sides are equal. Therefore, triangle ABC is an equilateral triangle.

Thus, the construction is justified.