Question

construct an equilateral triangle of side 5 cm

Answer 1

Let ABC be the ∆ ...... (1)Draw AB as base = 5 cm......... (2) Draw perpendicular bisector of AB....... (3) Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector........ (4) Do the same with point B and wherever those arcs meet name that point C......... (5) Thus ABC is the required ∆.

Answer 2

Answer:

This is the correct answer!!!!

Step-by-step explanation:

Draw AB as base = 5 cm......... (2) Draw perpendicular bisector of AB....... (3) Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector........ (4) Do the same with point B and wherever those arcs meet name that point C.........