Question

Construct an equilateral triangle PQR of side 6.5 cm. Measure ZP, ZQ and ZR. What do you conclude ?​

Answer 1

Answer:

construct it by your self and if you don't know watvh video on YouTube

Answer 2

Step-by-step explanation:

Given,

Construct an equilateral \triangle PQR△PQR of side 6.5\ cm6.5 cm and Measure \angle P, \angle Q\ and\ \angle R∠P,∠Q and ∠R

Following steps:

Draw a line segments PQ=6.5\ cmPQ=6.5 cm using scale.

PP as a center and 6.5\ cm6.5 cm as radius draw an arc.

Also QQ as a center and 6.5\ cm6.5 cm as radius draw an arc which cuts the before arc at point RR

Join PR\ and QRPR andQR

Hence, \triangle PQR△PQR is the required triangle.

We know,

In equilateral triangle, all three angle are equal.

So,

\angle P+\angle Q+\angle R=180∠P+∠Q+∠R=180

⇒3\angle P=1803∠P=180 (∵ All three are equal)

⇒\angle P=\frac{180}{3}∠P=

3

180

∴ \angle P=60\ degree∠P=60 degree

∴ \angle P, \angle Q\ and\ \angle R∠P,∠Q and ∠R value are 60\ degrees60 degrees