Question

construct an equilateral triangle PQR of side 6.5cm.measure angle P, angle Q and angle R. what do you conclude?,

Answer 1

$\triangle PQR$ is the required triangle.

Step-by-step explanation:

Given,

Construct an equilateral $\triangle PQR$ of side $6.5\ cm$ and Measure $\angle P, \angle Q\ and\ \angle R$

Following steps:

• Draw a line segments $PQ=6.5\ cm$ using scale.
• $P$ as a center and $6.5\ cm$ as radius draw an arc.
• Also $Q$ as a center and $6.5\ cm$ as radius draw an arc which cuts the before arc at point $R$
• Join $PR\ and QR$

Hence, $\triangle PQR$ is the required triangle.

We know,

In equilateral triangle, all three angle are equal.

So,

$\angle P+\angle Q+\angle R=180$

⇒$3\angle P=180$  (∵ All three are equal)

⇒$\angle P=\frac{180}{3}$

∴ $\angle P=60\ degree$

∴ $\angle P, \angle Q\ and\ \angle R$ value are $60\ degrees$