Question

Construct an equilateral triangle whose altitude is 4.5cm.
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Answer 1

Answer:

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Step-by-step explanation:

• Draw a line PQ
• Take any point L on this line.
• Construct perpendicular AL on PQ.
• Cut a line segment AD from D equal to 4.5 cm.
• Make angles equal to 30° at A on both sides of AD, say ∠CAD and ∠BAD where B and C lie on XY.
• Then, ABC is the required triangle.

Answer 2

Step-by-step explanation:

Construction :

Step 1: Draw a line segment AB of length 4.5 cms.

Step 2: Take 4.5 cms as radius and A as center, draw an arc.

Step 3: Take 4.5 cms as radius and B as center, draw and arc.

Step 4: Let C be the point where the two arcs intersect, join AC and BC and label the sides.

Thus, triangle ABC is the required equilateral triangle.

Justification :

By construction, AB=BC=CA ( Radius of equal arcs)

Since all sides are equal. Therefore, triangle ABC is an equilateral triangle.

Thus, the construction is justified.

solution