Construct an equilateral triangle with one side as 5 cm and justify the construction
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Let's assume side of equilateral triangle is 5.5 cm.
Steps of construction :
1) Draw a line segment AB of length 5.5 cm.
2) Taking 5.5 cm as radius, and A as centre, draw an arc.
3) Taking 5.5 cm as radius, and B as centre, draw another arc.
4) Let C be the point where the two arcs intersect . Join AC and BC and label the sides.
Thus, △ ABC is the required equilateral triangle.
Justification :
By construction, AB = AC = BC (Radius of equal arcs)
Since, all sides are equal , therefore, △ ABC is an equilateral triangle.
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