Construct an equilateral triangle with side 5cm.
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pls refer to the attachment ..................
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Step-by-step explanation:
(1)Draw AB as base = 5 cm
2) Draw perpendicular bisector of AB..
3Open the compass for 5 cm, keep the pointer at A and draw an arc such that it cuts the bisector
(4) Do the same with point B
5 Thus ABC is the required ∆.
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