Question

construct an equilateral triangle with side 6 CM​

Answer 1

Answer:

Step-by-step explanation:

Steps of Construction :

(i) Draw a line segment BC = 6 cm

(ii) With centres B and C and radius 6 cm, draw two arcs intersecting each other at A.

(iii) Join AB and AC

∆ ABC is the required equilateral triangle,

(iv) Draw the angle bisectors of ∠A, ∠B and ∠C.

These are the lines of symmetry which are three in numbers as the triangle is equilateral.

Answer 2

Answer:

Step-by-step explanation:

1. draw BC = 6 cm

2. with B as a centre and 6 cm radius draw an arc on one side of BC

3. with C as a centre and 6 cm as a radius , draw another arc on the same side of BC to intersect the former of arc at A

4. join AB and AC

then , Δ ABC is required equilateral triangle