Question

Construct an equilateral triangle xyz of side 5 cm and construct another triangle similar to triangle xyz such that each of its sides is a 4 by 5 of the sides of triangle xyz

Answer 1

Answer:

Step-by-step explanation:

Step 1 : Draw a line segment xy = 5 cm

Step 2: Using compass take length = 5 cm and draw an arc from point x

Step 3 : with same length of compass draw an arc from y such that it intersect earlier drawn arc at z

Step 4 : Join xz & yz

Δxyz  is constructed

We can repeat above step taking length = 4 cm

or we can get 4/5 of xy

Step 1 : take any acute angle at xy

Step 2 : taking some length take 5 subsequent points at equal distance

Step 3 : join last point (5th) with y

Step 4 take a line parallel to this line , passing though second last (4th point) , it will cut xy at some point such that 4/5 of xy

step 5 : Take a line parralle to yz passing through this point such that it cuts xz at some point

Δ is constructed with 4/5 of the sides of triangle

Answer 2

Answer:

Step-by-step explanation:

Step 1 : Draw a line segment xy = 5 cm

Step 2: Using compass take length = 5 cm and draw an arc from point x

Step 3 : with same length of compass draw an arc from y such that it intersect earlier drawn arc at z

Step 4 : Join xz & yz

Δxyz  is constructed

We can repeat above step taking length = 4 cm

or we can get 4/5 of xy

Step 1 : take any acute angle at xy

Step 2 : taking some length take 5 subsequent points at equal distance

Step 3 : join last point (5th) with y

Step 4 take a line parallel to this line , passing though second last (4th point) , it will cut xy at some point such that 4/5 of xy

step 5 : Take a line parralle to yz passing through this point such that it cuts xz at some point

Δ is constructed with 4/5 of the sides of triangle