Construct an equilateral triangle XYZ of side 5 cm and construct another triangle similar to triangle XYZ,such
that each of its sides is 4/5
of the sides of triangle XYZ (answer with a picture plz )
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Answer:
step1 : Draw a line segnent AB = 11cm (XY+YZ+ZX)
step2 : construct angle BAP = 30*
step3 :construct angle ABQ = 90*
step4 : Draw AR, the bisector of angle BAP
step5 : Draw BS, the bisector of angle ABQ. Let AR and BS intersect at X .
step6 : Draw perpendicular bisector of AX, which intersects AB at Y
step7 : Draw perpendicular bisector of XB, which intersects AB at Z
step8 : Join XY and XZ
Thus, XYZ is the required triangle
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