construct an equilatral triangle whose sise is 5 cm
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Steps of construction:
Draw a line segment LM = 5 cm.
Taking L as centre and radius 5 cm draw an arc.
Taking M as centre and radius draw an other arc intersecting previous arc at N.
Join LN and MN. ...
Taking M as centre and any suitable radius, draw an arc intersecting LM at P and MN at Q..
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