Construct an isoceles ∆ABC such that ii) base AC=4.5cm and base angle= 75°
( please gave the figure that you drawin while solving these question)
Answers
Answer:
Steps of Construction
In an isosceles triangle the base angles are equal
1. Construct a line segment AC=5AC=4.5 cm.
2. At the points A and C construct rays which makes and angle 75∘75∘ intersecting each other at the point B.
Therefore, ΔΔ ABC is the required triangle.
By measuring the equal sides is 9.69.6 cm in length approximately.
Answer:
(i) Steps of Construction :
We know that in an isosceles triangle base angles are equal.
(i) Draw a line segment BC = 4 cm.
(ii) At B and C, draw rays making an angle of 30° each intersecting each other at A.
∆ ABC is the required triangle.
On measuring the equal sides each is 2.5 cm (approx.) in length.
(ii) Steps of Construction :
We know that in an isosceles triangle, base angles are equal.(i) Draw a line segment AB = 6.2 cm
(ii) At A and B, draw rays making an angle of 45° each which intersect each other at C.
∆ABC is the required triangle.
On measuring the equal sides, each is 4.3 cm (approx.) in length.
(iii) Steps of Construction :
We know that base angles of an isosceles triangles are equal.
(i) Draw a line segment AC = 5 cm.
(ii) At A and C, draw rays making an angle of 75° each which intersect each other at B.
∆ ABC is the required triangle.
On measuring the equal sides, each is 9.3 cm in length.
Step-by-step explanation:
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