Question

construct an isosceles right angled triangle PQR in which angle Q = 90 and PR =PQ= 7.4 cm
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Answer 1

Step-by-step explanation:

Given:

⇒(i)r= radius=23.5=1.75 , h= depth of the well=10m 

⇒Curved surface area 

=2πrh

=(2×722×1.75×10)m2=110m2

⇒(ii) Cost of plastering = Rs 40 per m2

The cost of plastering the curved surface = Rs (110×40)= Rs 4400.