Construct an isosceles triangle abc in which base =4 cm, sum of the perpendicular from a to bc and side ab =6.5 cm
Answers
Answered by
8
draw the base 4cm
now,
at point b
take compass at 6.5cm by the help of scale
at point c
take compass at 6.5cm by the help of scale
now join the abc
now,
at point b
take compass at 6.5cm by the help of scale
at point c
take compass at 6.5cm by the help of scale
now join the abc
Attachments:
![](https://hi-static.z-dn.net/files/deb/655ec4711ebe1bfc331530d728ca664e.jpg)
Answered by
13
Step-by-step explanation:
Given: In △ABC, BC = 4 cm and sum of the perpendicular from A to BC and side AB = 6.5 cm.
Required : To construct ΔABC.
Steps of construction :
1.Draw any line segment BC = 4 cm.
2.Draw ‘p’ the perpendicular bisector of BC and let it intersect BC in R
3.Cut off PQ = 6.5 cm.
4.Join QB.
5.Draw the perpendicular bisector of BQ and let it intersect PQ in A.
6. Join AB and AC. Thus, ΔABC is the required triangle.
Attachments:
![](https://hi-static.z-dn.net/files/d9b/46d9b1762759bb788214a0d3ecc6c85c.png)
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