construct an isosceles triangle in which the length of each of its equal sides is 4.5 cm and the angle between them is 120
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Answered by
58
Steps of construction : -
1. Draw a line segment AB of 4.5 CM
2. Draw an angle of 120 degree and extend it to X then cut at C such that BC is equal to 4.5
3. Join A and C.
ABC is your required triangle with AB is equal to BC is equal to 4.5 CM
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jasveersinghrap7f82w:
grt keep it up...!
Answered by
18
Step-by-step explanation:
1. draw a linesegment a b of 4.5 cm.
2. draw an angle of 120 degree and extend it to X then cut it at such that BC is equal to 4.5
3. join a and c
- 4. ABC is your required triangle with a b is equal to BC is equal to 4.5 CM.
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