Construct an isosceles triangle whose altitude is 5 cm and vertex angle is 90°
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Follow these steps :
1. Draw a line XY of any length.
2. Draw perpendicular bisector of XY.
3. Cut an arc on the perpendicular bisector 5 cm above XY ( measure 5 cm from the compass). Name the intersection point as A.
4. Draw an angle of 45° on both sides of A towards XY. Let the angle arms cut XY at B and C respectively.
5. Triangle ABC is the required triangle.
1. Draw a line XY of any length.
2. Draw perpendicular bisector of XY.
3. Cut an arc on the perpendicular bisector 5 cm above XY ( measure 5 cm from the compass). Name the intersection point as A.
4. Draw an angle of 45° on both sides of A towards XY. Let the angle arms cut XY at B and C respectively.
5. Triangle ABC is the required triangle.
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Step-by-step explanation:
Follow these steps :
1. Draw a line XY of any length.
2. Draw perpendicular bisector of XY.
3. Cut an arc on the perpendicular bisector 5 cm above XY ( measure 5 cm from the compass). Name the intersection point as A.
4. Draw an angle of 45° on both sides of A towards XY. Let the angle arms cut XY at B and C respectively.
5. Triangle ABC is the required triangle.
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