Construct an isosceles triangle whose base is 10 cm and altitude is 3 cm and then construct another triangle whose side are 3/4 the corresponding sides of the isosceles triangle.
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❁❁ Refer To Image First .. ❁❁
Justification :---
By construction we have ,
→ x4 C || x3 C' { By BPT }
→ (B×3)/(B×4) = BC'/BC { By construction .}
→ (B×3)/(B×4) = 3/4
So,
→ BC'/BC = 3/4 ..
Now, we also have , CA || C'A' { By construction }.
Hence,
∆BC'A' ~ ∆BCA { By AA. }
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refer to the attachment mate ♡❄️♡
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