Question

Construct an isosceles triangle whose base is 4 cm and vertex angle 30°.Draw perpendicular frome the vertex on base.

Answer 1

Hey mate......

here's your answer......

Step1
Draw a line segment AB of length 4cm

Step2
Construct a 90° and a 60° angle at A.


Step3
Bisect the angle between the 90°and the 60° to obtain a 75°. Extend the Angle Bisector to a point D


Step4
: Repeat the process at B, extend the angle bisector to a point E


Step5:
Name the point of intersection of AD and BE as C.


Result: ΔABC is an isosceles Δ with base 4cm, vertex angle 30°.


Hope it helps ☺️

Answer 2

heya..

here is your answer..

In an Isosceles Δ, base angles are equal.

∴180°-30°= 2∠A

∴150°=2∠A

∴75° = each base angle

Step1: Draw a line segment AB of length 4cm

Step2: Construct a 90° and a 60° angle at A.

Step3: Bisect the angle between the 90°and the 60° to obtain a 75°. Extend the Angle Bisector to a point D

Step4: Repeat the process at B, extend the angle bisector to a point E

Step5: Name the point of intersection of AD and BE as C.

Result: ΔABC is an isosceles Δ with base 4cm, vertex angle 30°.

it may help you....