Construct an isosceles triangle whose base is 6cm ,altitude is 4 cm . Then construct another triangle whose sides are 3/4 times the corresponding sides of the isosceles triangle .
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take base as BC=6cm & draw perpendicular bisector of it and draw an arc of 4cm from intersecting point to intersect the perpendecular at A.join AB&AC.after take an acute angle CBX with base and mark 4points B1,B2,B3&B4 on BX ray and join B4&C,take B3C' parallel to B4C to intersect BC atC'from B3.and draw one more parallel C'A' which is parallel to CA which intersect BA at A'.there fore our required triangle A'BC' formed
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