Math, asked by ppatel7414, 5 months ago

Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another

triangle whose sides are 1⅟2 times the corresponding sides of the isosceles triangle.​

Answers

Answered by Anonymous
19

Answer:

REFER THIS DIAGRAM FOR CONSTRUCTION.

Steps of Construction

(i) Draw a line segment AB of length 8 cm.

(ii) Cut arcs taking point A and point B as the centre. Draw the line to intersect on line segment AB. Mark the intersecting point as point D.

(iii) Cut arc of length 4 cm on the same line which will be the altitude of the triangle.

(iv) Name the point as C. Then ABC is the isosceles triangle.

(v) Draw a line AX which makes an acute angle with AB and is opposite of vertex C.

(vi) Cut seven equal parts of line AX namely AA1, AA2, AA3.

(vii) Now join A2 to B. Draw a line A3B' parallel to A2B.

(viii) And then draw a line B'C' parallel to BC.

Hence,

AB'C' is the required triangle.

I HOPE IT WILL HELP YOU.....

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