Question

Construct an isosceles triangle whose base is 8cm and altitude is 4cm and then another triangle whose sides are ¹/2 times the corresponding sides of the isosceles triangle

Answer 1

Answer:

bhai mujhe brainliast banalo meh kitne din se koshish kar raha hu mujhe koi bhi brainliast nahi bana raha

Step-by-step explanation:

bhai mujhe brainliast banalo meh kitne din se koshish kar raha hu mujhe koi bhi brainliast nahi bana raha

bhai mujhe brainliast banalo meh kitne din se koshish kar raha hu mujhe koi bhi brainliast nahi bana raha bhai mujhe brainliast banalo meh kitne din se koshish kar raha hu mujhe koi bhi brainliast nahi bana raha

Answer 2

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Steps of construction:

1. Draw a base BC of length 8 cm.

2. Draw the perpendicular bisector of BC and name it PQ. Let it intersect BC in M.

3. From M, mark an arc A at a distance of 4 cm on PQ.

4. Join B−A and C−B. △ABC is the first isosceles triangle.

5. Extend BC and BA. Place the pointed end of the compass at C and mark an arc of radius CM on the opposite side of M on the extended segment BC. Mark the point as D (Since CM is half of BC, BD will be BC+0.5BC=1.5BC)

6. From D, draw a line parallel to AC and let it intersect the extended segment AB at E.

△EBD is the required similar triangle.

I HOPE ITS HELP YOU ☺️