Question

construct an isosceles triangle whose base is4 CM and then another triangle whose sides are 1 1/2 times the corresponding sides of the isosceles triangle(NEED AN STEP BY STEP EXPLAINATION) ​

Answer 1

Steps of construction:

1. Draw a base BC of length 8 cm.

2. Draw the perpendicular bisector of BC and name it PQ. Let it intersect BC in M.

3. From M, mark an arc A at a distance of 4 cm on PQ.

4. Join B−A and C−B. △ABC is the first isosceles triangle.

5. Extend BC and BA. Place the pointed end of the compass at C and mark an arc of radius CM on the opposite side of M on the extended segment BC. Mark the point as D (Since CM is half of BC, BD will be BC+0.5BC=1.5BC)

6. From D, draw a line parallel to AC and let it intersect the extended segment AB at E.

△EBD is the required similar triangle.

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