Question

construct an isosceles triangle whose perimeter is 11cm and the length of perpendiculate from verter on base is 2.3cm .
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Answer 1

Step-by-step explanation:

Take a line segment B'C' of 11 cm. Draw perpendicular at its mid point(perpendicular bisector). Mark the midpoint as D. Take a point A at distance 2.3 cm on perpendicular bisector and mark it as A. Join A and B'. Make angle equal to

< AB'D at A on line segment AB' and name this as < ABD, where B lies on line segment B'D..Take A point C on line segment C'D such that AB = AC.

∆ ABC is the requiredbtriangle.