Math, asked by gunjan34, 1 year ago

construct an isosceles triangle with the length of equal sides as 4.5 cm and that of base side as 5.5cm. Measure the angles opposite of the equal sides. what do you conclude?


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Answers

Answered by AMAYTRIPATHI
31
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Angle opposite to equal sides are equal and measures 50 degree

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Answered by ishwaryam062001
2

Answer:

To discover the angles contrary the equal sides, we can use the truth that in an isosceles triangle, the angles contrary the equal aspects are equal.

Step-by-step explanation:

From the above question,

To assemble an isosceles triangle with equal facets of 4.5 cm and a base facet of 5.5 cm, we can observe these steps:

  1. Draw a straight line phase AB of size 5.5 cm.
  2. From A and B, draw two arcs of radius 4.5 cm each.
  3. These arcs will intersect at two points, C and D.
  4. Join C and D with a straight line section to structure the isosceles triangle.
  5. The graph of the built triangle is proven below:

To discover the angles contrary the equal sides, we can use the truth that in an isosceles triangle, the angles contrary the equal aspects are equal.

Let perspective ACB = perspective BCA = x (in degrees)

Then perspective ABC = one hundred eighty - 2x (in degrees)

Using the cosine rule, we can discover the fee of x:

cos(x) = (4.5^2 + 4.5^2 - 5.5^2) / (2 * 4.5 * 4.5)

cos(x) = -0.0667

      x = cos^-1 (-0.0667)

      x ≈ 101.4 degrees

Therefore,

             The angles contrary the equal aspects of the isosceles triangle are each about 101.4 degrees.

From this,

          We can conclude that the triangle is obtuse-angled, due to the fact each angles contrary the equal facets are higher than ninety degrees.

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