Question

Construct an isoscles triangle ABC in which BC =4cm, AB =5cm and AC =5 cm. ​

Answer 1

Answer:

Given: In △ABC, BC = 4 cm and sum of the perpendicular from A to BC and side AB = 6.5 cm.

Required : To construct ΔABC.

Steps of construction :

1.Draw any line segment BC = 4 cm.

2.Draw ‘p’ the perpendicular bisector of BC and let it intersect BC in R

3.Cut off PQ = 6.5 cm.

4.Join QB.

5.Draw the perpendicular bisector of BQ and let it intersect PQ in A.

6. Join AB and AC. Thus, ΔABC is the required triangle.

Step-by-step explanation:

plz follow me

Answer 2

Answer:

first draw a rough figure, then draw BC of length 4cm, then mark 5cm on compass. keep the needle of the compass on B and draw an arc. then with the same length keep the needle of the compass on C and cut another arc. The point where the two arcs cut will be the 'A'

I hope this may help you dear please mark me as brainliest please even I have taken a lots of Time to understand and solve it please dear..