Question

construct an isosles triangle whose base is 6 cm and attitude 4 cm construct a similar triangle whose sides 3/2 times the corresponding sides of given isosceles triangle​

Answer 1

step of construction :

Step I  : Draw BC=8cm

Step II : Construct XY , the perpendicular bisector of line segment BC meeting BCat M.

Step III : Along MP cut -off MA=4cm

Step IV : Join BA and CA , then ΔABC so obtained is the required ΔABC 

Step  V ;  Extend BC to D , Such that BD=12cm(=23×87cm)

Step Vi  : Draw DE∣∣CA meeting BAproduced at E .Then ΔEBD is the required triangle.

Justification  : 

 

Since DE∣∣CA

∴ΔABC∼ΔEBDandABEB=CADE=BCBD=812=23

Hence we have the new triangle similar to the given triangle whose are 121i.e.23times the corresponding sides of the isosceles ΔABC.