Math, asked by abhisheksingh852006, 5 hours ago

Construct an traingle , in which angle Y is 58 degree , angle X is 46 degree and primeter of traingle is 10.5 cm.​

Answers

Answered by netrazatale001
0

Step-by-step explanation:

Steps of construction:

(1) Draw seg PQ of 10.5cm length.

(2) Draw a ray making angle of 29

at point P.

(3) Draw another ray making an angle of 23

at point Q.

(4) Name the point of intersection of the two rays as Z.

(5) Draw the perpendicular bisector of seg PZ and seg QZ.

Name the points as Y and X respectively where the perpendicular bisectors intersect line PQ.

(6) Draw seg XZ and seg YZ.

Therefore, ΔXYZ is the required triangle.

solution

Answered by nagiarts
0

Answer:

Steps of construction:

i: Draw a line segment QR of 10.5cm.

ii: From point Q draw a ray QD at 58° and from R draw a ray RE at 46°

iii: Draw an angle bisector of Q and R, two angle bisectors intersect each other at point X.

iv: Draw a line bisector of QX and XR respectively these two-line bisectors intersect at point Y and Z

v: Join XY AND XZ.

vi: Δ XYZ is required triangle

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