Question

Construct an triangle ABC with bc=6cm,ab=5cm and angle ABC=60 then construct a triangle whose side are 3/4 of the corresponding side of ∆ABC

Answer 1

Step-by-step explanation:

1. Draw base BC of 6cm
2. draw angle B as 60°
3. taking B as center 5 cm radius we draw an arc which got intersect the ray at point A
4. join AC
5. draw another line downward BX from point B. (see example from book)
6. make 4 single arc divided equally

now solve yourself by seeing example from book and side book

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