Question

Construct an triangle PQR in which PQ=5.6cm ,PR=7 cm and QR=4.5cm​

Answer 1

Step-by-step explanation:

the answer in above mentioned in photograph

Answer 2

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Steps of Construction :

(1) Draw a line PQ = 5.5 cm.

(2) From Q as a centre draw an arc QR = 7.5 cm.

(3) From P as a centre draw an arc PR = 6 m, which intersects previous arc at R.

(4) Join PR and QR.

(5) Now, draw interior bisectors of ∠P, ∠QR ∠R which meets each other at point S.

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