Construct and prove that AB+CD=12.9cm, if AB=3.9cm and CD=9.3.please tell me
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Draw a line segment DC =9.6cm
With D as center , draw an angle measure 60
∘
. Now , cut off it with an arc 3.2cm cm called point A.
Now , draw a parallel AB to CD
Taking C as center , cut an arc B measuring 3.2cm on previous parallel line.
Draw a line segment BE =3.2cm from arc B
Join B to E and C
Thus we have required trapezium ABCD in which ∠ A =120
∘
and ∠ B =60
∘
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