Question

construct angle abc=60 digree ab=6cm,bc=7cm,take radius 2cm and construct a circle such that it touches both the arms of the angle

Answer 1

Answer:

take base as bc=7 cm. the make an arc of 2 cm with a compas from the vertex. now with the same radius keep the needle on the point of arc that touches the line bc and cut arc on the existing one. now join the vertex to the intersection of the arc and you get 60 degree

using compass and scale

Answer 2

Answer:

Steps of Construction:

1) Draw a line segment AB = 7 cm.

2) Draw angle ∠ABC = 60° with the help of compass.

3) Cut off BC = 8 cm.

4) Join A and C.

5) The triangle ABC so formed is the required triangle.

i) Draw the perpendicular bisector of BC. The point situated on this line will be equidistant from B and C.

ii) Draw the angle bisector of ∠ABC . Any point situated on this angular bisector is equidistant from lines AB and BC.

The point which fulfills the condition required in (i) and (ii) is the intersection point of bisector of line BC and angular bisector of ∠ABC.

P is the required point which is equidistant from AB and AC as well as from B and C.

On measuring the length of line segment PB, it is equal to 4.5 cm.