construct angle Def such that DE 5cm DF 3cm and my angle EDF90.
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first draw a line of 5cm . then take any point of that line and draw semicircle using compass with any length but less than 3cm . now make 90° angle with compass only . now draw a line of 3cm from the point (which is the centre of the semicircle) crossing through the 90° angle .
hence your angle is formed of 90°
the photo is also here...
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hence your angle is formed of 90°
the photo is also here...
I hope it helped you...
please mark it as brainliest...
^_^
:)
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this is the construction
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