Question

construct angle PQR if PQ is 5cm angle PQR is 105 degree and angle QPR =40 degree? (Hint : Recall angle -sum property) ​

Answer 1

hey mate!

In △PQR,∠P+∠Q+∠R=180° (Angle Sum Property)∠P+105°+40°=180°∠P+145°=180°∠P=180°−145°∠P=35°Steps of construction :(1) Draw a line segment PQ=5 cm(2) Draw an line PX at point P at an angle 35° .(3) Draw an line QY at point Q at an angle 105° .(4) PX and QY intersects at point R.(5) Join PR and QR.Thus , PQR is the required triangle.

Answer 2

Firstly made a line segment of 5 cm and name its point P and Q then then made a angle of 105 degree from q and make a line segments crossing it then name it's R and then then meet us line segment of 40 degree from p to R.