Question

** Construct APQR, in which QR = 6 cm, LQ-60 and PR - PQ-2cm.​

Answer 1

Answer:

Steps of Construction

(i) Draw QR = 6 cm.

(ii) Construct ∠YQR = 60°.

(iii) Produce YQ to Y' to form line YQY'.

(iv) From ray QY' cut-off line segment QS = 2 cm.

(v) Join SR.

(vi) Draw perpendicular bisector of RS which intersect QY at P.

(vii) Join PR to obtain required DPQR.

Justification

As P lies on the perpendicular bisector of RS. Therefore, PR = PS = PQ + QS = PQ + 2 cm

⇒ PR - PQ = 2cm

Hence, △PQR is the required triangle.